4x^2-8x+19=15

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Solution for 4x^2-8x+19=15 equation: 



4x^2-8x+19=15

We move all terms to the left:

4x^2-8x+19-(15)=0

We add all the numbers together, and all the variables

4x^2-8x+4=0

a = 4; b = -8; c = +4;
Δ = b2-4ac
Δ = -82-4·4·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{8}{8}=1$

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